1, According to the law of the definite composition, elements form compounds in the same ratios by mass each time the compound is produced. Using the theoretical percent by mass of magnesium in MgO, calculate the mass of oxygen that will combine with 12. 25g of Mg and the mass of MgO that will be formed.
2. Which compound has the greatest percentage by mass of Magnesium?
a, MgCl2 b, Mg ( NO3)2 c, Mg3(PO4)2 d, MgSO4
3, Magnesium sulfide is 43,1% Mg by mass. How many tons of Sulfur can be produced by the thermal decomposition of 20. 5 tons of magnesium sulfide?
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If you can show me the balanced equation of the reaction, I will help you.
Edit:
1.
2Mg + O_2 ==> 2MgO
12. 25g Mg * 1 mol Mg/ 24. 3g Mg = 0. 504 moles Mg
0. 504 moles Mg * 1 mol O_2/ 2 mol Mg = 0. 252 mol O_2
0. 252 mol O_2 * 32. 00g O_2/ 1 mol O_2 = 8. 064 g O_2
0. 504 moles MgO * 40. 3 g MgO / 1 mol MgO = 20. 31 g MgO
2.
a) MgCl_2
Mg = 24. 3 g
Cl_2 = 2(35. 5 g) = 71 g
% Mg/ MgCl_2 = 24. 3 g/ 95. 3 g * 100% = 25. 5% Mg (Highest % Mg is found here)
b) Mg(NO_3)_2
Mg = 24. 3
(NO_3)_2 = [14. 0 g + 3(16. 0 g)]2 = 124 g (NO_3)_2
% Mg/ Mg(NO_3)2 = 24. 3 g / 148. 3 g * 100% = 16. 4% Mg
c) Mg_3(PO_4)2
Mg = 24. 3 g
(PO_4)_2 = [31 g + 4(16. 0) g]2 = 190 g (PO_4)_2
% Mg/ Mg(PO_4)_2 = 24. 3 g / 214. 3 g * 100% = 11. 34% Mg
d) MgSO_4
Mg = 24. 3 g
SO_4 = 32. 1 g + 4(16. 0 g) = 96. 1 g SO_4
% Mg / MgSO_4 = 24. 3 g / 120. 4 g * 100% = 20. 2% Mg
3.
Mg + S ==> MgS
% 43. 1 Mg by mass = 43. 1 g Mg in a 100 g of MgS.
20. 5 tons of MgS decomposed = 20. 5 tons * 1,000,000 g / 1 ton = 20,500,000 g
20,500,000 g = 2. 05×10^6 g MgS
2. 05×10^6 g MgS * 1 mol MgS/ 56. 4 g MgS = 36,3437. 5 moles of MgS
43. 1 g Mg * 1 mol Mg / 24. 3 g Mg * 36,3437. 5 mol MgS/ 1 mol Mg * 1 mol S/ 1 mol MgS * 32. 1 g S/ 1 mol S = 20,692,157. 0 g
Therefore, Sulfur produced: 20,692,157. 0 g S * 1 ton/ 1,000,000 g = 20. 7 tons
Peace out homeboy!!