Why do you need 40 grams of calcium and 32 grams to 72 grams of sulfa calcium sulfide? Sorry its probably so simple, but im really bad in science: / If I could explain how you got the answer that would be great! (To help you learn) Thank you very much. (:
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= Atomic weight of calcium you 40Peso atomic sulfur = 32The reaction Ca + S = CaS. . . . . . . . . . . . . . . . . . 40 + 32 = 72
B. Well o. b. . Have you ever seen the art created out of nothing? Probably not. You can get the energy with e = m * c ^ 2, but you need to know that. So if you can not question anything, then the problem starts with what you have to be at the end is. So if you start with 40 g and 32 g of something, then you start with a total of 72 grams of something that must score 72 grams of something.
mass casla Ca + S = reagents are added to the mass of the product if there is additional reactivos.Ca 40g/moleS = 40 = 32 = 72g/moleya 32g/molede that the reaction does not need to balance you Need one amount of each reagent mol (atomic mass, if I remember correctly) find the atomic mass of each element of the periodic table and see.
The formula of a compound that indicates the number of “parts” of each element is composed of – for example, water is H20 (2 is subscript), which means that two atoms of hydrogen and oxygen CaS calcium 1.Sulfuro with a molecular weight of 72g/mole.Proporcionar their atomic weights are correct for Ca and S are combined to 72. [If the water is H30 in place, its weight would be 3 * + O = H 3 * 1 +16 = 19 g instead of the real 18 / mol. The molecular weights of the periodic table (see source). ]