How many grams of sodium sulfide are formed when: 1. 80 g of hydrogen sulfide is bubbled into a solution. . . ?

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1. Dr.A says

   moles of H2S = 1. 80 g/34. 082 g / mol = 0. 0528H2S + 2 + 2 NaOH = Na2S H2Omoles NaOH required = 0. 0528 x 2 = 0. 106moles NaOH = 2. 40 g / 40 g / mol = 0. 060 => limitanteNa2S moles of reagent = 0. 060 / 2 = 0. 030Na2S mass = 0. 030 x 78 mol. 0456 g / mol = February. 34g

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   May 20, 2010, 10:41 pm