What is the empirical formula and molecular phosphorus sulfide and alumina?

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1. ? says

   in 100 g of P consisting of demolishing 27. 87 / 31 =. 9moles S 72. 13/32. 06 = 2. 5dividir by. 9, we obtain P: S = 1:2. 5 or 2:5 weighting formula empíricafórmula formula P2S5 = 2 * 31 5 * 32 = 222 which is half the molecular weight on a molecular esP4S10moles Al = 52. 91 / 27 = 1. 95 ~ 2mol O = 47. = 08/16 ~ 3fórmula empirical formula Al2O3peso = 2 * 27 +3 * 16 = 102 = molecular weight Al2O3 molecularpara formula we

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   March 31, 2010, 7:15 am