Ammonium sulfide with silver nitrate? Please write how you I!
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ammonium sulfide (NH4) 2S (Note 4 and 2 are the indices) is the ammonium ion NH4 know is that has a +1 charge. The sulfide ion, S, is in charge -2. . . therefore, has two ammonium ion to a silver nitrate is sulfuro.El Ag (NO3) (The 3 is an index). Ag has a +1 charge and a charge-NO3 1.La molecular equation (NH4) 2S + 2AG (NO3) —> 2NH4 (NO3) + Ag2SSi recall the charges it makes sense. . . also to balance the equation. why there is a 2 in front of silver nitrate and ammonium nitrate before, so it has the same number of molecules / ions in each lado.La ionic equation is when they break the ion add to all this: 2NH4 (1) + S (-2) 2 Ag (1) + NO3 (-1 )—> 2NH4 (1) + NO3 (-1) + 2AG (1) + S (-2) net ionic equation to cancel the ions are the same on both sides and write what you have left. In the present case. . . all ions cancel. . . if the reagents were aqueous (dissolved in water). You have not specified. . . if one of them is a solid, then you must write the states. . . and a solid can be split into ions, so that will affect the net ionic equation.