a. sodiob chloride. magnesioc chloride. potasiod chloride. acetate sodio. Copper (II) chloride want the answers are B and E, but I can not understand why and how to solve these problems.
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easy. Anything that u is a table of solubility. to separate ions, which u have to do is throw one i. e. to an insoluble salt containing. in our case, we acetate and sulfur. while the acetates are generally soluble (such as nitrates) are not sulfuros.si u take a look at this picture of solubility, u’ll see that the copper sulfide and magnesium sulfide are quite insoluble, while all other sulfides (sodium and potassium) are soluble. . Mg and Cu if the correct answer.
His solution anions 2, S2 and OAC.La best thing you can do is add a substance that may cause any anión.En, copper ion reacts with sulfur to form insoluble CuS. Thus, the anion in the solution is chloride ion. while the CUS ppted removed by filtration.