Aqueous potassium sulfide and lead (II) nitrate react to produce solid lead (II) sulfide and aqueous potassium nitrate
When you write this equation, should it look as so:
K2S(aq) + Pb(NO3)2(aq) –> PbS(s) + K(NO3)?
AH, small mistake. Apparently i wrote the 2 coefficient on my paper though 
, Thank you i just wanted to make sure i was on the right track.
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Your equation is write except for the coefficients. If you compare the products side to the reactants side, you will see that there are 2 potassium ions on the left and only 1 on the right and 2 nitrate ions on the left and only one on the right. Coincidentally if you put a 2 in front of the potassium nitrate compound on the products side you will have a completely balanced equation.
So the answer would be
K2S(aq) + Pb(NO3)2(aq) –> PbS(s) + 2K(NO3)